ESTIMATING OF COLUMN

Covering, Side = 2.5cm, top = 2 cm, Bottom = 5 cm.

a) R.C.C WORK:-
★Base : part: v1= 1.5x1.5x0.2 = 0.45 m3
★Traphizoidal part: v2 = k/6 (A1+A2+4 A3) [A3 = (A1+A2)/2]
0.30/6 {1.5²+0.25²+4*(1.5²+0.25²)/2}=0.347m³

★Column part: v3 = 4x0.25x0.25
=0.25m³

Total = 1.047m³

Dry volume = 1.5x1.047 = 1.57m³
sum of ratio = 1+2+4 = 7

Cement = (1.57x1x30)/7 = 7 bag
Sand = (1.57x2)/7 = 0.448m³
Brick = (1.57x4)/7 = 0.90m³
0.90x300 = 270 Nos

b) M.S. bar Calculation:
★10mm base main bar @ 15cm c/c:
Length = 150-2x2.5+2x10x(10/10)
              = 165cm
              = 1.65m

N = (150-2x2.5)/15 +1
    = 11 Nos.

Weight of bar = (10²/162.2)x11x1.65
                          = 11.19 kg x 2
                          = 22.38 kg.

★16mm dia-main bar:
Length = 3.5+0.5+0.3+0.2-0.05-0.01x0.08+0.075+2x10x0.016
              = 4.585m.

Weight of bar = {(16)²/162.2}x4x4.585
                          = 28.94 kg

★6mm dia -tie@ 20cm c/c:
Length = 2(20+20)+30
              = 110cm
              = 1.1m

N = {(350+50+30+20-2-5-1x2-1.6-10)/20}+1
   =23 Nos.

Weight of bar: (6²/162.2)x23x1.1
                         = 5.61 kg

Total M.S Rod = 56.93 kg
                          =0.5693 quintal
                                                      Ans: